43 lines
1.2 KiB
Lua
43 lines
1.2 KiB
Lua
-- Implement the is_anagram() function below, so that it returns true if
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-- the two passed strings are anagrams of each other. Any non-
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-- alphabetical characters in the string should be ignored.
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--
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-- Solution --------------------------------------------------------------------
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function is_anagram(str1, str2)
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-- Your implementation here
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end
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-- Tests -----------------------------------------------------------------------
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local luaunit = require("luaunit.luaunit")
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function test_listen_is_anagram_of_silent()
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luaunit.assertTrue(is_anagram("listen", "silent"))
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end
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function test_astronomers_is_anagram_of_moon_starers()
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luaunit.assertTrue(is_anagram("astronomers", "moon starers"))
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end
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function test_dormitory_is_anagram_of_dirty_room()
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luaunit.assertTrue(is_anagram("dormitory", "dirty room"))
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end
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function test_foo_is_not_anagram_of_bar()
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luaunit.assertFalse(is_anagram("foo", "bar"))
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end
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function test_foo_is_not_anagram_of_of()
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luaunit.assertFalse(is_anagram("foo", "of"))
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end
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function test_bar_is_not_anagram_of_barn()
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luaunit.assertFalse(is_anagram("bar", "barn"))
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end
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function test_barn_is_not_anagram_of_bar()
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luaunit.assertFalse(is_anagram("barn", "bar"))
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end
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os.exit(luaunit.LuaUnit.run())
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