sudoku-solver/sud.c

/*
 * Copyright (C) 2022 Camden Dixie O'Brien
 *
 * This program is free software: you can redistribute it and/or modify
 * it under the terms of the GNU Affero General Public License as
 * published by the Free Software Foundation, either version 3 of the
 * License, or (at your option) any later version.
 *
 * This program is distributed in the hope that it will be useful, but
 * WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
 * Affero General Public License for more details.
 *
 * You should have received a copy of the GNU Affero General Public
 * License along with this program.  If not, see
 * <https://www.gnu.org/licenses/>.
 */

#include "lut.h"
#include "sud.h"

#include <stdio.h>
#include <stdlib.h>

#define MAX_FILL_ATTEMPTS 32

#define CELLINIT 0x01ff

static void init(struct sudoku *sud)
{
	for (unsigned i = 0; i < NCELLS; ++i)
		sud->cells[i] = CELLINIT;
}

bool load(struct sudoku *sud, const char *ptr)
{

	init(sud);

	for (unsigned i = 0; i < NCELLS; ++i) {
		if (ptr[i] == '0')
			continue;
		if (update(sud, i, ptr[i] - '1') != OK)
			return false;
	}

	return true;
}

void save(struct sudoku *sud, char *ptr)
{
	for (unsigned i = 0; i < NCELLS; ++i) {
		if (DET(sud->cells[i]))
			*ptr++ = '1' + VAL(sud->cells[i]);
		else
			*ptr++ = '0';
	}
}

enum update_res update(struct sudoku *sud, unsigned i, unsigned val)
{
	const uint16_t clearmask = ~(1 << val);

	/* Update possible values of cells in same row, column and
	 * segment. */
	for (unsigned j = 0; j < NGROUP; ++j) {
		sud->cells[rowidx_lut[i][j]] &= clearmask;
		sud->cells[colidx_lut[i][j]] &= clearmask;
		sud->cells[segidx_lut[i][j]] &= clearmask;
	}

	/* Set the cell's value. */
	sud->cells[i] = 0;
	sud->cells[i] |= DETMASK;
	sud->cells[i] |= val << VALSHIFT;

	return OK;
}

void print(const struct sudoku *sud)
{
	for (unsigned r = 0; r < NDIGITS; ++r) {
		/*
		 * Print horizontal divider if on a segment boundary (but not
		 * at the start).
		 */
		if (r != 0 && r % SEGLEN == 0)
			puts("------+-------+------");

		for (unsigned c = 0; c < NDIGITS; ++c) {
			/*
			 * Print vertical divider if on a segment boundary (but
			 * not at the start).
			 */
			if (c != 0 && c % SEGLEN == 0)
				fputs("| ", stdout);

			if (DET(sud->cells[IDX(r, c)]))
				printf("%u ", VAL(sud->cells[IDX(r, c)]) + 1);
			else
				fputs("  ", stdout);
		}
		putchar('\n');
	}
}

static void zerocounts(unsigned counts[NDIGITS])
{
	for (unsigned i = 0; i < NDIGITS; ++i)
		counts[i] = 0;
}

static bool checkcounts(unsigned counts[NDIGITS])
{
	for (unsigned i = 0; i < NDIGITS; ++i) {
		if (counts[i] != 1)
			return false;
	}
	return true;
}

enum check_res check(const struct sudoku *sud)
{
	unsigned r, c, i, j, digitcounts[NDIGITS];

	/* Check each row. */
	for (r = 0; r < NDIGITS; ++r) {
		zerocounts(digitcounts);
		for (c = 0; c < NDIGITS; ++c) {
			if (!DET(sud->cells[IDX(r, c)]))
				return INCOMPLETE;
			++digitcounts[VAL(sud->cells[IDX(r, c)])];
		}
		if (!checkcounts(digitcounts))
			return INCORRECT;
	}

	/* Check each column. */
	for (c = 0; c < NDIGITS; ++c) {
		zerocounts(digitcounts);
		for (r = 0; r < NDIGITS; ++r) {
			if (!DET(sud->cells[IDX(r, c)]))
				return INCOMPLETE;
			++digitcounts[VAL(sud->cells[IDX(r, c)])];
		}
		if (!checkcounts(digitcounts))
			return INCORRECT;
	}

	/* Check each segment. */
	for (i = 0; i < NDIGITS; ++i) {
		zerocounts(digitcounts);
		for (j = 0; j < NDIGITS; ++j) {
			r = 3 * (i / 3) + j / 3;
			c = 3 * (i % 3) + j % 3;
			if (!DET(sud->cells[IDX(r, c)]))
				return INCOMPLETE;
			++digitcounts[VAL(sud->cells[IDX(r, c)])];
		}
		if (!checkcounts(digitcounts))
			return INCORRECT;
	}

	/* If we've got this far, all is well. */
	return SOLVED;
}

bool filled(const struct sudoku *sud)
{
	for (unsigned r = 0; r < NDIGITS; ++r) {
		for (unsigned c = 0; c < NDIGITS; ++c) {
			if (!(DET(sud->cells[IDX(r, c)])))
				return false;
		}
	}
	return true;
}