/*
 * Copyright (C) 2022 Camden Dixie O'Brien
 *
 * This program is free software: you can redistribute it and/or modify
 * it under the terms of the GNU Affero General Public License as
 * published by the Free Software Foundation, either version 3 of the
 * License, or (at your option) any later version.
 *
 * This program is distributed in the hope that it will be useful, but
 * WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
 * Affero General Public License for more details.
 *
 * You should have received a copy of the GNU Affero General Public
 * License along with this program.  If not, see
 * <https://www.gnu.org/licenses/>.
 */

#include "solve.h"

#include <stdio.h>

int solve(struct sudoku *sud)
{
	unsigned r, c, n, i, j, val, np, pr, pc;
	bool match;

	for (n = 0;; ++n) {
		match = false;

		/* Check if only one place a value can go on each row. */
		for (r = 0; r < NDIGITS; ++r) {
			for (val = 0; val < NDIGITS; ++val) {
				np = 0;
				for (c = 0; c < NDIGITS; ++c) {
					if (!sud->cells[r][c].det && sud->cells[r][c].pvals[val]) {
						pr = r;
						pc = c;
						++np;
						if (np > 1)
							break;
					}
				}
				if (np == 1) {
					if (update(sud, pr, pc, val) != OK)
						return -1;
					match = true;
				}
			}
		}

		/* Check if only one place a value can go on each column. */
		for (c = 0; c < NDIGITS; ++c) {
			for (val = 0; val < NDIGITS; ++val) {
				np = 0;
				for (r = 0; r < NDIGITS; ++r) {
					if (!sud->cells[r][c].det && sud->cells[r][c].pvals[val]) {
						pr = r;
						pc = c;
						++np;
						if (np > 1)
							break;
					}
				}
				if (np == 1) {
					if (update(sud, pr, pc, val) != OK)
						return -1;
					match = true;
				}
			}
		}

		/* Check if only one place a value can go in each segment. */
		for (i = 0; i < NDIGITS; ++i) {
			for (val = 0; val < NDIGITS; ++val) {
				np = 0;
				for (j = 0; j < NDIGITS; ++j) {
					r = SEGLEN * (i / SEGLEN) + j / SEGLEN;
					c = SEGLEN * (i % SEGLEN) + j % SEGLEN;
					if (!sud->cells[r][c].det && sud->cells[r][c].pvals[val]) {
						pr = r;
						pc = c;
						++np;
						if (np > 1)
							break;
					}
				}
				if (np == 1) {
					if (update(sud, pr, pc, val) != OK)
						return -1;
					match = true;
				}
			}
		}

		/* Exit if no matches. */
		if (!match)
			return n;
	}
}