Draw shortest path to exit instead of all visited cells

This commit is contained in:
Camden Dixie O'Brien 2024-11-04 21:34:06 +00:00
parent b89b4b64b2
commit c2a043a8b1

37
main.c
View File

@ -24,6 +24,7 @@
#define PX(x) ((x) << 3)
#define GOAL (GRID_SIZE - 1)
#define MAX_PATH_LENGTH (MAZE_SIZE * MAZE_SIZE)
typedef enum { LEFT, RIGHT, UP, DOWN } dir_t;
@ -111,8 +112,10 @@ static void generate(vec2_t start)
}
}
static bool solve(vec2_t start)
static bool solve(vec2_t start, vec2_t *path, vec2_t **end)
{
*path++ = start;
for (int i = 0; i < 4; ++i) {
const vec2_t next = {
.x = start.x + steps[i].x,
@ -130,17 +133,19 @@ static bool solve(vec2_t start)
const bool unvisited = !maze[next.x][next.y].visited;
if (accessible && unvisited) {
maze[next.x][next.y].visited = true;
draw_visited(next);
maze[im.x][im.y].visited = true;
draw_visited(im);
nanosleep(&solve_pause, NULL);
if ((GOAL == next.x && GOAL == next.y) || solve(next))
if (GOAL == next.x && GOAL == next.y) {
*path++ = next;
*end = path;
return true;
}
if (solve(next, path, end))
return true;
}
}
}
--path;
return false;
}
@ -199,15 +204,25 @@ int main(void)
// Solve
const vec2_t solve_start = { 0, 0 };
vec2_t path[MAX_PATH_LENGTH], *path_end;
maze[0][0].visited = true;
XSetForeground(dpy, ctx, visited_col);
draw_visited(solve_start);
solve(solve_start);
solve(solve_start, path, &path_end);
// Draw exit path
const int x = PX(MARGIN + GRID_SIZE + 1), y = PX(MARGIN + GRID_SIZE);
XFillRectangle(dpy, window, ctx, x, y, PX(1), PX(1));
XFlush(dpy);
// Draw solution path
const vec2_t *prev = &solve_start;
for (const vec2_t *p = path; p < path_end; ++p) {
const vec2_t im = {
.x = (prev->x + p->x) / 2,
.y = (prev->y + p->y) / 2,
};
draw_visited(*p);
draw_visited(im);
nanosleep(&solve_pause, NULL);
prev = p;
}
draw_visited(exit);
sleep(1);
}